Array Reversal in C Hacker Rank Solution

Hello coders, In this post, you will learn how to solve the Array Reversal in C Hacker Rank Solution. This problem is a part of the HackerRank C Programming Series.

Array Reversal in C Hacker Rank Solution

Problem

Given an array, of size n, reverse it.
Example: If array, arr = [1,2,3,4,5], after reversing it, the array should be, arr[5,4,3,2,1].

Task

Input Format :

The first line contains an integer, n, denoting the size of the array. The next line contains n space-separated integers denoting the elements of the array.

Constraints :

• 1<=n<=1000
• 1<=arri<=1000, where arri is the ith element of the array.

Output Format :

The output is handled by the code given in the editor, which would print the array.

Sample Input 0

6
16 13 7 2 1 12

Sample Output 0

12 1 2 7 13 16

Explanation 0

Given array, arr = [16,13,7,2,1,12]. After reversing the array, arr = [12,1,2,7,13,16]

Sample Input 1

7
1 13 15 20 12 13 2

Sample Output 1

2 13 12 20 15 13 1

Sample Input 2

8
15 5 16 15 17 11 5 11

Sample Output 2

11 5 11 17 15 16 5 15 

Array Reversal in C Hacker Rank Solution

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int num, *arr,*arr2,i;
    scanf("%d", &num);
    arr = (int*) malloc(num * sizeof(int));
    for(i = 0; i < num; i++) {
        scanf("%d", arr + i);
    }
    arr2 = (int*) malloc(num * sizeof(int));
    for(i=1;i<=num;i++)
    {
        arr2[i-1] = arr[num-i];
    }
    for(i = 0; i < num; i++)
        printf("%d ", *(arr2 + i));
    return 0;
}

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