C Program To Check Number Is Armstrong Or Not Using If/Else Statements

#include<stdio.h>
#include<conio.h>
int main()
{
int number, temp, remainder, result = 0, n = 0 ;
printf("Enter an integer: ");
scanf("%d", &number);
temp = number;
// Finding the number of digits
while (temp != 0)
{
temp /= 10;
++n;
}
temp = number;
// Checking if the number is armstrong
while (temp != 0)
{
remainder = temp%10;
result += pow(remainder, n);
temp /= 10;
}
if(result == number)
printf("%d is an Armstrong number\n", number);
else
printf("%d is not an Armstrong number\n", number);
return 0;
}

Output:

Input- Enter an integer: 1634 Output- 1634 is an Armstrong number Input- Enter an integer:156 Output- 156 is not an Armstrong number
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