Day 7: Regular Expressions | 10 Days of JavaScript – Hacker Rank Solution

Day 7: Regular Expressions | 10 Days of JavaScript – Hacker Rank Solution: Hey Guy’s In this post we are solving Day 7: Regular Expressions which is a part of 10 Days of JavaScript Series.

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Day 7: Regular Expressions | 10 Days of JavaScript – Hacker Rank Solution

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In this challenge, we use a Regular Expression to evaluate a string. Check out the attached tutorial for more details.


Complete the function in the editor below by returning a RegExp object, re, that matches any string s that begins and ends with the same vowel. Recall that the English vowels are aeio, and u.


  • The length of string s is >= 3.
  • String s consists of lowercase letters only (i.e., [a-z]).

Output Format

The function must return a RegExp object that matches any string s beginning with and ending in the same vowel.

Sample Input 0


Sample Output 0


Explanation 0

This string starts with (and ends in) a consonant, so it cannot start and end with the same vowel.

Sample Input 1


Sample Output 1


Explanation 1

This string ends in a consonant, so it cannot start and end with the same vowel.

Sample Input 2


Sample Output 2


Explanation 2

This string starts and ends with the same vowel (a).

Sample Input 3


Sample Output 3


Explanation 3

This string starts with the vowel a but ends in the vowel o.

Day 7: Regular Expressions | 10 Days of JavaScript – Hacker Rank Solution

'use strict';
let inputString = '';
let currentLine = 0;
process.stdin.on('data', inputStdin => {
    inputString += inputStdin;
process.stdin.on('end', _ => {
    inputString = inputString.trim().split('\n').map(string => {
        return string.trim();
function readLine() {
    return inputString[currentLine++];
function regexVar(str) {
//  ^ => first item matches:
// () => stores matching value captured within
// [aeiou] => matches any of the characters in the brackets
// . => matches any character:
// + => for 1 or more occurrances (this ensures str length > 3)
// \1 => matches to previously stored match.
    // \2 looks for matched item stored 2 instances ago
    // \3 looks for matched item stored 3 ago, etc
//  $ ensures that matched item is at end of the sequence
    let re = /^([aeiou]).+\1$/;
    return re;
function main() {
    const re = regexVar();
    const s = readLine();

Disclaimer: The above Problem (Day 7: Regular Expressions) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.


10 days of javascript hackerrank
Answer: Join over 16 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. 10 Days of JavaScript

How can I learn JavaScript in 10 days?
Answer: Many free and paid courses and tutorials are available to learn JavaScript. For in-depth knowledge, you can also purchase a few good books like A Smarter Way to Learn JavaScript and Effective JavaScript: 68 Specific Ways to Harness the Power of JavaScript. However, to start working on projects, you need only a little theory and more hands-on, so we recommend you to take up tutorials and short courses that will get you onboard quickly.

Does hacker rank have JavaScript?
Answer: They might not have a specific practice tutorial for it. But you can solve any of their general problems using Javascript.

What is HackerRank JS?
Answer: The HackerRank Skills Certification Test is a standardized assessment to help developers prove their coding skills.

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