Deque-STL in C++ Hacker Rank Solution

Hello coders, In this post, you will learn how to solve the Deque-STL in C++ Hacker Rank Solution. This problem is a part of the HackerRank C++ Programming Series.

Deque-STL in C++ Hacker Rank Solution
Deque-STL in C++ Hacker Rank Solution

Deque-STL in C++ Hacker Rank Solution


You inherited a piece of code that performs username validation for your company’s website. The existing function works reasonably well, but it throws an exception when the username is too short. Upon review, you realize that nobody ever defined the exception.

The inherited code is provided for you in the locked section of your editor. Complete the code so that, when an exception is thrown, it prints Too short: n (where n is the length of the given username).

Input Format :

The first line contains an integer, t, the number of test cases.
Each of the t subsequent lines describes a test case as a single username string, n.

Constraints :

  • 1 <= t <= 1000
  • 1<= |u| <= 100
  • The username consists only of uppercase and lowercase letters.

Output Format :

You are not responsible for directly printing anything to stdout. If your code is correct, the locked stub code in your editor will print either Valid (if the username is valid), Invalid (if the username is invalid), or Too short: n (where n is the length of the too-short username) on a new line for each test case.

Sample Input :


Sample Output :

Too short: 2

Explanation :

Username Me is too short because it only contains 2 characters, so your exception prints Too Short : 2.
All other validation is handled by the locked code in your editor.

Deque-STL in C++ Hacker Rank Solution

#include <iostream>
#include <deque>
using namespace std;
void printKMax(int arr[], int n, int k)
	//Write your code here.
	/* Deque-STL in C++ - Hacker Rank Solution START */
    deque<int> Qi(k);
    int i;
    for (i = 0; i < k; i++)
        while ((!Qi.empty()) && (arr[i] >= arr[Qi.back()]))
    for ( ; i < n; i++) {
        cout << arr[Qi.front()] << " ";
        while ((!Qi.empty()) && (Qi.front() <= i - k))
        while ((!Qi.empty()) && (arr[i] >= arr[Qi.back()]))
    cout << arr[Qi.front()] << endl;
    /* Deque-STL in C++ - Hacker Rank Solution END */
int main()
	int t;
	cin >> t;
		int n,k;
    	cin >> n >> k;
    	int i;
    	int arr[n];
      		cin >> arr[i];
    	printKMax(arr, n, k);
  	return 0;

Disclaimer: The above Problem (Deque-STL in C++ – ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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