Digit Frequency in C Hacker Rank Solution

Hello coders, In this post, you will learn how to solve the Digit Frequency in C Hacker Rank Solution. This problem is a part of the HackerRank C Programming Series.

Digit Frequency in C Hacker Rank Solution

Problem

Given a string, S, consisting of alphabets and digits, find the frequency of each digit in the given string.

Input Format :

The first line contains a string, num which is the given number.

Constraints :

1<=len(num)<=1000
All the elements of num are made of english alphabets and digits.

Output Format :

Print ten space-separated integers in a single line denoting the frequency of each digit from 0 to 9.

Sample Input 0

a11472o5t6

Sample Output 0

0 2 1 0 1 1 1 1 0 0

Explanation 0

In the given string:

• 1 occurs two times. 
• 2,4,5,6 and 7 occur one time each.
• The remaining digits 0,3,8 and 9 don’t occur at all.

Sample Input 1

lw4n88j12n1

Sample Output 1

0 2 1 0 1 0 0 0 2 0

Sample Input 2

1v88886l256338ar0ekk

Sample Output 2

1 1 1 2 0 1 2 0 5 0 

Digit Frequency in C Hacker Rank Solution

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
    char *s;
    s = malloc(1024 * sizeof(char));
    scanf("%s", s);
    s = realloc(s, strlen(s) + 1);
    int len = strlen(s), i;
    int arr[10];
    for(i = 0; i < 10; i++)
        arr[i] = 0;
    for(i = 0; i < len; i++) {
        if(s[i] >= '0' && s[i] <= '9') {
            arr[(int)(s[i] - '0')]++;
        }
    }
    for(i = 0; i < 10; i++)
        printf("%d ", arr[i]);
    printf("\n");
    free(s);
    return 0;
}

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