Gross Salary Codechef Solution

Hello coders, today we are going to solve Gross Salary CodeChef Solution whose Problem Code is FLOW011.

Problem

In a company an emplopyee is paid as under: If his basic salary is less than Rs. 1500, then HRA = 10% of base salary and DA = 90% of basic salary.

If his salary is either equal to or above Rs. 1500, then HRA = Rs. 500 and DA = 98% of basic salary. If the Employee’s salary is input, write a program to find his gross salary.

NOTE: Gross Salary = Basic Salary + HRA + DA

Input 

The first line contains an integer T, total number of testcases. Then follow T lines, each line contains an integer salary.

Output

For each test case, output the gross salary of the employee in a new line. Your answer will be considered correct if the absolute error is less than 10^-2.

Constraints

• 1 ≤ T ≤ 1000
• 1 ≤ salary ≤ 100000

Example

Sample Input 

3
1203
10042
1312

Sample Output 

2406.00
20383.16
2624

Gross Salary CodeChef Solution in Python

T = int(input())
for i in range(T):
    n = int(input())
    if n < 1500:
        salary = n + (90*n/100) + (10*n/100)
        print(salary)
    else:
        salary = n + (98*n/100) + 500
        print(salary)

Gross Salary CodeChef Solution in CPP

#include <stdio.h>
int main(){
	int a;
	scanf("%d",&a);
	while(a--){
		long b;
		float d;
		scanf("%li",&b);
		if(b<1500)
			printf("%g\n",b+0.1*b+0.9*b);
		else{
			printf("%g\n",b+500+b*0.98);
		}
	}
}

Gross Salary CodeChef Solution in JAVA

import java.util.*;
class CodeChef
{
    public static void main(String args[]){
        Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        for(int i=0;i<n;i++)
        {
            int a = s.nextInt();
            float sal;
            if(a<1500)
            {
                sal = (float)(a + (0.10*a)+(0.90*a));
            }
            else
            {
                sal = (float) (a+500+(0.98*a));
            }
            System.out.println(sal);
        }
    }
}

Disclaimer: The above Problem (Gross Salary) is generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.