Group() Groups() Groupdict() in Python HackerRank Solution

Hello coders, In this post, you will learn how to solve Group() Groups() Groupdict() in Python HackerRank Solution. This problem is a part of the Python Hacker Rank series.

Group() Groups() Groupdict() in Python HackerRank Solution

problem

group()
A group() expression returns one or more subgroups of the match.
Code :

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com')
>>> m.group(0)       # The entire match
'username@hackerrank.com'
>>> m.group(1)       # The first parenthesized subgroup.
'username'
>>> m.group(2)       # The second parenthesized subgroup.
'hackerrank'
>>> m.group(3)       # The third parenthesized subgroup.
'com'
>>> m.group(1,2,3)   # Multiple arguments give us a tuple.
('username', 'hackerrank', 'com')

groups()
A groups() expression returns a tuple containing all the subgroups of the match.
Code :

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com')
>>> m.groups()
('username', 'hackerrank', 'com')

groupdict()
A groupdict() expression returns a dictionary containing all the named subgroups of the match, keyed by the subgroup name.
Code :

>>> m = re.match(r'(?P<user>\w+)@(?P<website>\w+)\.(?P<extension>\w+)','myname@hackerrank.com')
>>> m.groupdict()
{'website': 'hackerrank', 'user': 'myname', 'extension': 'com'}

Task :

You are given a string S.
Your task is to find the first occurrence of an alphanumeric character in S(read from left to right) that has consecutive repetitions.

Input Format :

A single line of input containing the string S.

Constraints :

• 0 < len(S) < 100

Output Format :

Print the first occurrence of the repeating character. If there are no repeating characters, print -1.

Sample Input :

..12345678910111213141516171820212223

Sample Output :

1

Explanation :

.. is the first repeating character, but it is not alphanumeric.
1 is the first (from left to right) alphanumeric repeating character of the string in the substring 111.

Group() Groups() Groupdict() in Python HackerRank Solution

import re
expression=r"([a-zA-Z0-9])\1+"
m = re.search(expression,input())
if m:
    print(m.group(1))
else:
    print(-1)

Disclaimer: The above Problem (Group() Groups() Groupdict() in Python) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.