Hex Color Code in Python HackerRank Solution

Hello coders, In this post, you will learn how to solve Hex Color Code in Python HackerRank Solution. This problem is a part of the Python Hacker Rank series.

Hex Color Code in Python - HackerRank Solution
Hex Color Code in Python HackerRank Solution

Hex Color Code in Python HackerRank Solution


CSS colors are defined using a hexadecimal (HEX) notation for the combination of Red, Green, and Blue color values (RGB).
Specifications of HEX Color Code
■ It must start with a ‘#’ symbol.
■ It can have 3 or digits 6.
■ Each digit is in the range of 0 to F. ( 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, A, B, C, D, E and F).
■ A – F letters can be lower case. (a, b, c, d, e and f are also valid digits).

Example :

Valid Hex Color Codes
Invalid Hex Color Codes

You are given N lines of CSS code. Your task is to print all valid Hex Color Codes, in order of their occurrence from top to bottom.

CSS Code Pattern

	Property: Value;

Input Format :

The first line contains N, the number of code lines.
The next N lines contains CSS Codes.

Constraints :

  • 0 < N < 50

Output Format :

Output the color codes with ‘#’ symbols on separate lines.

Sample Input :

    color: #FfFdF8; background-color:#aef;
    font-size: 123px;
    background: -webkit-linear-gradient(top, #f9f9f9, #fff);
    background-color: #ABC;
    border: 2px dashed #fff;

Sample Output :


Explanation :

#BED and #Cab satisfy the Hex Color Code criteria, but they are used as selectors and not as color codes in the given CSS.
Hence, the valid color codes are:
Note: There are no comments ( // or /* */) in CSS Code.

Hex Color Code in Python HackerRank Solution

import re
T = int(input())
in_css = False
for _ in range(T):
    s = input()
    if '{' in s:
        in_css = True
    elif '}' in s:
        in_css = False
    elif in_css:
        for color in re.findall('#[0-9a-fA-F]{3,6}', s):

Disclaimer: The above Problem (Hex Color Code in Python) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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