Java Exception Handling Hacker Rank Solution

Hello coders, In this post, you will learn how to solve Java Exception Handling Hacker Rank Solution. This problem is a part of the Java programming series. 

One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions.

Java Exception Handling Hacker Rank Solution

Objective

You are required to compute the power of a number by implementing a calculator. Create a class MyCalculator which consists of a single method long power(int, int). This method takes two integers, n and p, as parameters and finds . 

Problem Statement: Click Here

Java Exception Handling Hacker Rank Solution

import java.util.*;
import java.util.Scanner;
class MyCalculator {
    long power(int n, int p) throws Exception {
        if (n < 0 || p < 0) {
            throw new Exception("n or p should not be negative.");
        } else if (n == 0 && p == 0) {
            throw new Exception("n and p should not be zero.");
        } else {
            return (long) Math.pow(n, p);
        }
    }
}
class Solution {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            MyCalculator my_calculator = new MyCalculator();
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}

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