# Java Substring Hacker Rank Solution

Hello coders, In this post, you will learn how to solve Java Substring Hacker Rank Solution. This problem is a part of the Java programming series.

One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions.

## Java Substring Hacker Rank Solution

### Problem :

Given a string,8 , and two indices, start and end, print a substring consisting of all characters in the inclusive range from start to end-1 . You’ll find the String class’ substring method helpful in completing this challenge.

Input Format

The first line contains a single string denoting 8.
The second line contains two space-separated integers denoting the respective values of start and end .

Constraints

• String  consists of English alphabetic letters (i.e., ) only.

Output Format

Print the substring in the inclusive range from start to end-1 .

Sample Input

``````Helloworld
3 7``````

Sample Output

``lowo``

Explanation

In the diagram below, the substring is highlighted in green:

### Java Substring Hacker Rank Solution

```import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
/* Save input */
Scanner scan = new Scanner(System.in);
String A = scan.next();
String B = scan.next();
scan.close();
/* Sum lengths */
System.out.println(A.length() + B.length());
/* Compare lexicographical ordering */
System.out.println(A.compareTo(B) > 0 ? "Yes" : "No");
/* Print the Strings in desired format */
System.out.println(capFirstLetter(A) + " " + capFirstLetter(B));
}
private static String capFirstLetter(String str) {
if (str == null || str.length() == 0) {
return "";
} else {
return str.substring(0,1).toUpperCase() + str.substring(1);
}
}
}```

Disclaimer: The above Problem (Java Substring) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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