In this post, we are going to solve the Jump Game Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.

Problem
You are given an integer array nums
. You are initially positioned at the array‘s first index, and each element in the array represents your maximum jump length at that position.
Return true
if you can reach the last index, or false
otherwise.
Example 1:
Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
Example 2:
Input: nums = [3,2,1,0,4] Output: false Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index.
Constraints:
1 <= nums.length <= 104
0 <= nums[i] <= 105
Now, let’s see the leetcode solution of Jump Game Leetcode Solution.
Jump Game Leetcode Solution in Python
class Solution: def canJump(self, nums: List[int]) -> bool: i = 0 reach = 0 while i < len(nums) and i <= reach: reach = max(reach, i + nums[i]) i += 1 return i == len(nums)
Jump Game Leetcode Solution in CPP
class Solution { public: bool canJump(vector<int>& nums) { int i = 0; for (int reach = 0; i < nums.size() && i <= reach; ++i) reach = max(reach, i + nums[i]); return i == nums.size(); } };
Jump Game Leetcode Solution in Java
class Solution { public boolean canJump(int[] nums) { int i = 0; for (int reach = 0; i < nums.length && i <= reach; ++i) reach = Math.max(reach, i + nums[i]); return i == nums.length; } }
Note: This problem Jump Game is generated by Leetcode but the solution is provided by Chase2learn This tutorial is only for Educational and Learning purposes.
NEXT: Merge Intervals