# No Idea in python HackerRank Solution

Hello coders, In this post, you will learn how to solve No Idea in python HackerRank Solution. This problem is a part of the Python Hacker Rank series.

## No Idea in python HackerRank Solution

### problem

There is an array of n integers. There are also 2 disjoint sets, A and B, each containing m integers. You like all the integers in set A and dislike all the integers in set B. Your initial happiness is 0. For each i integer in the array, if i (- A , you add 1 to your happiness. If i (- B, you add -1 to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since A and B are sets, they have no repeated elements. However, the array might contain duplicate elements.

#### Constraints :

• 1 <= n <= 10^5
• 1 <= m <= 10^5
• 1 <= any integer in the input <= 10^9

#### Input Format :

The first line contains integers n and m separated by a space.
The second line contains n integers, the elements of the array.
The third and fourth lines contain m integers, A and B, respectively.

#### Output Format :

Output a single integer, your total happiness.

```3 2
1 5 3
3 1
5 7
```

```1
```

#### Explanation :

You gain 1 unit of happiness for elements 3 and 1 in set A. You lose 1 unit for 5 in set B. The element 7 in set B does not exist in the array so it is not included in the calculation.
Hence, the total happiness is 2 – 1 = 1.

### No Idea in python HackerRank Solution

```# No Idea in python - Hacker Rank Solution START
io = input().split()
m = int(io[0])
n = int(io[1])
storage = list()
count = 0
storage = list(map(int, input().strip().split()))
A = set(map(int, input().strip().split()))
B = set(map(int, input().strip().split()))
for i in storage:
if i in A:
count = count+1
if i in B:
count = count-1
print(count)
# No Idea in python - Hacker Rank Solution END```

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