Piling Up in python HackerRank Solution

Hello coders, In this post, you will learn how to solve Piling Up in python HackerRank Solution. This problem is a part of the Python Hacker Rank series.

Piling Up in python HackerRank Solution

problem

There is a horizontal row of n cubes. The length of each cube is given. You need to create a new vertical pile of cubes. The new pile should follow these directions: if cubei is on top of cubej then sideLengthj >= sideLengthi.
When stacking the cubes, you can only pick up either the leftmost or the rightmost cube each time. Print “Yes” if it is possible to stack the cubes. Otherwise, print “No”. Do not print the quotation marks.

Input Format :

The first line contains a single integer T, the number of test cases.
For each test case, there are 2 lines.
The first line of each test case contains n, the number of cubes.
The second line contains n space separated integers, denoting the sideLengths of each cube in that order.

Constraints :

• 1 <= T <= 5
• 1 <= n <= 10^5
• 1 <= sideLength <= 2^31

Output Format :

For each test case, output a single line containing either “Yes” or “No” without the quotes.

Sample Input :

2
6
4 3 2 1 3 4
3
1 3 2

Sample Output :

Yes
No

Explanation :

In the first test case, pick in this order: left -4 , right -4 , left -3 , right – 3, left – 2, right – 1. In the second test case, no order gives an appropriate arrangement of vertical cubes. 3 will always come after either 1 or 2.

Piling Up in python HackerRank Solution

from collections import deque
N = int(input())
for _ in range(N):
    flag = True
    input()
    d = deque(map(int, input().strip().split()))
    if(d[0] >= d[-1]):
        max = d.popleft()
    else:
        max = d.pop()
    while d:
        if(len(d)==1):
            if(d[0] <= max):
                break
            else:
                flag = False
                break
        else:
            if(d[0]<=max and d[-1]<=max):
                if(d[0]>=d[-1]):
                    max = d.popleft()
                else:
                    max = d.pop()
            elif(d[0]<=max):
                max = d.popleft()
            elif(d[-1]<=max):
                max = d.pop()
            else:
                flag = False
                break
    if flag:
        print("Yes")
    else:
        print("No")

Disclaimer: The above Problem (Piling Up in python) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.