# The Report SQL Hacker Rank Solution

Hello coders, In this post, you will learn how to solve The Report SQL Hacker Rank Solution. This problem is a part of the SQL Hacker Rank series.

## The Report SQL Hacker Rank Solution

### Problem

You are given two tables: Students and GradesStudents contains three columns IDName and Marks.

Ketty gives Eve a task to generate a report containing three columns: NameGrade and MarkKetty doesn’t want the NAMES of those students who received a grade lower than 8. The report must be in descending order by grade — i.e. higher grades are entered first. If there is more than one student with the same grade (8-10) assigned to them, order those particular students by their name alphabetically. Finally, if the grade is lower than 8, use “NULL” as their name and list them by their grades in descending order. If there is more than one student with the same grade (1-7) assigned to them, order those particular students by their marks in ascending order.

Write a query to help Eve.

Sample Input

Sample Output

``````Maria 10 99
Jane 9 81
Julia 9 88
Scarlet 8 78
NULL 7 63
NULL 7 68
``````

Note

Print “NULL”  as the name if the grade is less than 8.

Explanation

Consider the following table with the grades assigned to the students:

So, the following students got 89 or 10 grades:

### The Report SQL Hacker Rank Solution

```SELECT IF(g.Grade<8, NULL, s.Name), g.Grade, s.Marks FROM Students AS s
JOIN Grades AS g ON s.Marks BETWEEN g.Min_Mark AND g.Max_Mark ORDER BY g.Grade DESC, s.Name, s.Marks;
```

Disclaimer: The above Problem (The Report) generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes.

Sharing Is Caring